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(Solved): The decrease in stress is given by \sigma =\sigma _(0)exp(-(t)/(\tau )). At 20\deg C, a stress of 9 ...
The decrease in stress is given by
\sigma =\sigma _(0)exp(-(t)/(\tau )). At
20\deg C, a stress of
9MPais applied to an elastomeric material at a constant stress. After 25 days, the stress decreases to
8MPa. What is the relaxation time
\tau for this material?
T=days (*Round to the nearest integer.) What will be the stress after 50 days? Answer:
,MPa(*show up to the 2nd decimal place.) A
